Re: [DML] High Voltage Coils, High Octane Fuel
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Re: [DML] High Voltage Coils, High Octane Fuel



On 12 Nov 2003 12:14:38 -0000, <dmcnews@xxxxxxxxxxxxxxx> wrote:

I've been reading this section now for a while. There are a couple of points I need to make. The voltage of the ignition is regulated by the "spark gap". This happens to be the spark plug. The voltage will only build up until a spark can avalanche across the spark plug electrodes. It usually requires the most voltage at times of peak compression, which is during full throttle. To take advantage of being capable of generating greater voltage, you have to widen the spark gap. If you don't do that all your really buying is longer lasting spark plugs. The next topic is the ignition coil. When you apply a voltage across its primary coil, the voltage on the output begins to build up. As the voltage is building up, the current being drawn by the primary coil is inductive, and the ferrite (magnetic) core is still charging greater. Once the current or voltage has been there for a short period of time, the ferrite core will be fully magnetized. After this point, the current draw will not be inductive, but will turn to resistive. This is the saturation point. Now the coil will start increasing the amount of current its drawing, because at approximately 1 ohm, its almost a short circuit. This is the reason for the ballast resistor, to limit current so you don't burn up the primary coil windings. Usually ignition coils with different magnetic cores tuned for higher frequencies (RPM's) will saturate at a higher rpm and may require greater resistance (ballast resistors) to prevent overheating or burning up the primary circuit at lower rpm's.

Paul Gress
vin 10193

Date: Tue, 11 Nov 2003 04:47:05 -0000 From: "David Teitelbaum" <jtrealty@xxxx> Subject: Re: High Voltage Coils, High Octane Fuel

Getting technical now there is a property called "saturation". Simply
stated you can only put so much energy into a coil, any more and it
won't give you anymore output. Using a coil with a higher ratio of
turns in it may give you more output voltage but only up to the
saturation point. That point is reached as the RPM's increase.

[moderator snip}






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