Re: [DML] Intercooler

[Martin Gutkowski - DMC Ltd <martin@xxxxxxxxxxxxxx>]

Well, yeah...

Assuming a perfect system (HA!)

Engine is 2849cc 4-stroke, meaning it draws half its capacity every 
revolution

So 5000 x 2849 x 0.5 / 1000 = 7122.5 l/min

(which according to www.onlineconversion.com)

= 251.5 cf/min

Now that's at a pressure of 1 bar (atmosphere) and you are talking about 
7psi (14.7psi = 1bar) = 0.48bar of boost

so that's 1.48 x 251 = 371 cfm at 7psi of boost (and what fantastic 
swapping of units I must admit!)

- I'm not sure I'm right about the flow under boost but it seems to 
makes sense to me!

I'd go bigger because the PRV can safely be revved to 6500rpm if the 
breathing's good.

Martin

Nick wrote:

>Is there a figure or 
>a formula to know how much air a Delorean engine will consume at 
>5000 rpm?
>  
>







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